Linux Foundation To offer A free course with Edx saving 2400$
Linux foundation have announced a free course with Edx early this week its the time to get register at Edx and enjoy the free offer
Here is the full detail offer by Linux Foundation
The Linux Foundation, the nonprofit organization dedicated to accelerating the growth of Linux and collaborative development, today announced it is building a Massive Open Online Course (MOOC) program with edX, the nonprofit online learning platform launched in 2012 by Harvard University and Massachusetts Institute of Technology (MIT). More than 31 universities have partnered with edX and nearly two million people have accessed its courses online since it launched just 18 months ago.
Additionally, The Linux Foundation is announcing a new Authorized Training Partner program with AT Computing, Enea, OlinData and SolutionWare among the first members. Together the new MOOC program and Advanced Training Partner program will increase the ways in which Linux professionals can access high-quality, technically advanced, community-based training materials.
As Linux has become the fabric of computing, demand for talent to support it has skyrocketed. For example, according to the 2014 Linux Jobs Report, nine in 10 hiring managers are hiring Linux pro’s in the next six months. And, while talent isn’t bounded by geography, sometimes access to advanced Linux training has been limited. Employers are seeking Linux professionals in a market where not enough exist, while professionals struggle to find affordable, accessible training opportunities to advance their careers.
The Linux Foundation and edX are partnering to develop a MOOC program that will help address this issue by making basic Linux training materials available to all for free. Previously a $2,400 course, Introduction to Linux will be the first class available as a MOOC and will be free to anyone, anywhere. The Linux Foundation is among a new group of member organizations edX announced today who will contribute courses to the platform.